I remain calm and cool among tumult and fury, I hide treasures and creatures you could hardly fathom, I will crush those I welcome in deeply, I am dark yet beautiful.
Underwater in the deep ocean. Even when storms brew, the water deep below the surface is calm and cool. Thousands of treasures have been lost in sunken ships, and amazing creatures live at deep depths of the ocean. At extreme depths, the pressure is crushing. It is extremely dark deep in the ocean, yet also beautiful.
The next number in the series counts the previous numbers. Thus the first number is 1, which is one 1, or 11. To describe 11, you have two 1’s, or 21. Now you have one 2 and one 1, so the next number is 1211. The solution is to continue describing the previous number using only numbers.
A black dog is sleeping in the middle of a black road that has no streetlights and there is no moon. A car coming down the road with its lights off steers around the dog. How did the driver know the dog was there?
1. How do you put a giraffe into a refrigerator? 2. How do you put an elephant into a refrigerator? 3. The Lion King is hosting an animal conference. All the animals attend except one. Which animal doesn’t attend? 4. There is a river you must cross but it is used by crocodiles and you don’t have a boat. How can you cross safely?
1. Open the refrigerator, put the giraffe in and close the door. It’s not complicated. 2. Open the refrigerator, take out the giraffe, then put in the elephant and close the door. 3. The elephant. He’s still in the refrigerator. After all, you just put him there. 4. Jump into the river and swim across. The crocodiles are at the Lion King’s animal meeting. I admit, this is not a typical brain teaser, but it amused me.
A bird. They are hatched and raised in trees (nests), don’t have teeth in the traditional meaning of teeth and they lay eggs, which look nothing like a bird.
The problem works out to a set of three equations: b + c + d = 22 a + c + e = 22 a + b + c + d + e = 30
Solving for c = 14, leaving d = 8 – b and e = 8 – a. In other words, c must be 14, but the other two numbers just have to add up to 8. The requirement that they be unique rules out 4 + 4, so you’re left to choose from the following combations for b + d and a + e: 0 + 8 1 + 7 2 + 6 3 + 5
I give you a group of three. One is sitting down, and will never get up. The second eats as much as is given to him, yet is always hungry. The third goes away and never returns.