Brandon was walking around at the carnival. A man called out from a booth and said, “If I can write your exact weight on this piece of paper, you have to pay me $50. If I can’t do it, I’ll pay you $50.”
Brandon checked the booth for a scale but saw nothing. He agreed. Since your weight can fluctuate by a pound or two, he decided that no matter what number the man wrote, he would just say he weighed a pound more or less. In the end, the man in the booth won the $50. How did he do it?
1. Each letter represents a different digit from 1 to 9 2. The total of each row is 17. 3. (B × B) + B + F = A 4. C × F = EF (a 2-digit number, not their product)
A + B + C = 17 D + E + F = 17 B2 + B + F = A C × F = EF
To begin with, B has to be a 1 or 2 or else A wouldn’t be a single digit. Plug in B = 2, gives you 6 + F = A, meaning F and A can only be (1,7) or (3,9). To get 17, C would have to be 8 or 6, but those values don’t work for C × F = EF. So B must be 1.
2 + F = A means F and A can be (2,4), (3,5), (4,6), (5,7), (6,8) or (7,9). To get 17 on the top row, the only option that leaves C as a single digit is F = 5 and A = 7.
C × F = EF 9 × 5 = 45, so E = 4 and D = 8 to make the second row equal to 17.
An 18-wheeler is crossing a 4 kilometer bridge that can only support 10,000 kilograms and that’s exactly how much the rig weighs. Halfway across the bridge a 30 gram sparrow lands on the cab, but the bridge doesn’t collapse. Why not?
Since the bridge is 4 kilometers long, the halfway point would be 2 kilometers. The 18-wheeler would have used much more than 30g of fuel to drive 2 kilometers.
Imagine you’re alone in a boat with a large hole in the bottom. Sharks are swimming around you on all sides and the boat is sinking fast. How do you survive?