My family sings Christmas carols at the hospital where my wife works.
We do this every year and since we started, have not missed a single year.
The next time we do this will be the 18th consecutive Christmas.
My 15 year old daughter has been every time.
She was born in March 1999 so the first year she came was December 1999 (before her 1st birthday).
Her first time was when she was 0, second time when she was 1, third time when she was 2, etc…
Now that she is 15, she has been 16 times. Oh and of course she was also present in December 1998 in her mum’s belly, due to be born the next March.
So, a total of 17 times and next time will be the 18th.
Thanks to Michael for submitting this real-life brain teaser about his family.
My first is in FLOWER and in ROSE
My second is in FORK and well as HOSE
My third is in CROCUS but not in GNOME
My fourth is in RAKE never in HOME
My fifth is in HOE and also in WEEDS
My sixth is in SHEARS though not in SEEDS
My seventh is in LADYBIRD not in CREATURE
1. Each letter represents a different digit from 1 to 9
2. The total of each row is 17.
3. (B × B) + B + F = A
4. C × F = EF (a 2-digit number, not their product)
A + B + C = 17
D + E + F = 17
B2 + B + F = A
C × F = EF
To begin with, B has to be a 1 or 2 or else A wouldn’t be a single digit. Plug in B = 2, gives you 6 + F = A, meaning F and A can only be (1,7) or (3,9). To get 17, C would have to be 8 or 6, but those values don’t work for C × F = EF. So B must be 1.
2 + F = A means F and A can be (2,4), (3,5), (4,6), (5,7), (6,8) or (7,9). To get 17 on the top row, the only option that leaves C as a single digit is F = 5 and A = 7.
C × F = EF
9 × 5 = 45, so E = 4 and D = 8 to make the second row equal to 17.