1 lb = A 2 lbs + A = B 3 lbs = B 4 lbs = A + B 5 lbs + A + B = C 6 lbs + B = C 7 lbs + B = A + C 8 lbs + A = C 9 lbs = C 10 lbs = A + C 11 lbs + A = B + C 12 lbs = B + C 13 lbs = A + B + C 14 lbs + B = D 15 lbs + B = A + D 16 lbs + A = D 17 lbs = D 18 lbs = A + D 19 lbs + A = B + D 20 lbs = B + D 21 lbs = A + B + D 22 lbs + A + B = C + D 23 lbs + B = C + D 24 lbs + B = A + C + D 25 lbs + A = C + D 26 lbs = C + D 27 lbs = A + C + D 28 lbs + A = B + C + D 29 lbs = B + C + D 30 lbs = A + B + C + D
Enderman are normally passive, but they become hostile if a player looks directly at them. The Enderman will stare back until the player looks away, and then attack the player. A bucket of water is the best way to defeat an Enderman.
A six-digit number represented by ABCDEF (each letter represents a different number) can be multiplied by 2, 3, 4, 5, and 6 and yet no new digits appear in the result. As a matter of fact, all the digits are rotated. What is the number?
Alfred is at the bank to cash his $200 check. He tells the cashier he would like some one dollar bills, ten times as many two dollar bills and the rest in fives.
How many of each denomination does the cashier need to give Alfred?
We know that in order to give the rest of the amount in fives, the sum of the one and two dollar bills needs to be divisible by five (i.e. end in 0 or 5).
If we start with a single one dollar bill, we’d need ten two dollar bills to satisfy the request, making $21. But we need a sum that is divisible by 5. So we keep going up, like so: