Half-way up the hill, I see thee at last, lying beneath me with thy sounds and sights — A city in the twilight, dim and vast, with smoking roofs, soft bells, and gleaming lights.
What does man love more than life Fear more than death or mortal strife What the poor have, the rich require, and what contented men desire, What the miser spends and the spendthrift saves And all men carry to their graves?
This is a place. The first letter is after A and before Z but nowhere in between. You can bring as many people as you want, as long as they’re all dead. Where is it?
The cemetery. The letter C is after A and before Z, and it’s not found in the word “between”. The cemetery won’t take live ones. Fortunately I don’t speak from experience on that.
The word vex. “v” is Roman numeral 5, which is odd. “x” is Roman numeral 10, which is even. “e” is the base of the natural logarithm and is irrational (e = 2.718281828…). Its mantissa (the part to the right of the decimal point) is infinitely long.
This is a most unusual paragraph. How quickly can you find out what is so unusual about it? It looks so ordinary you’d think nothing was wrong with it – and in fact, nothing is wrong with it. It is unusual though. Why? Study it, think about it, and you may find out. Try to do it without coaching. If you work at it for a bit it will dawn on you. So jump to it and try your skill at figuring it out. Good luck! Don’t blow your cool!
I hesitated to add this because it’s poorly worded, ambiguous and the answer could be almost anything. I prefer teasers with a single answer, but there you go.
If you came up with a different answer and can explain how you did it, don’t think you’re wrong. It’s probably just as valid. Feel free to share yours in the comments.
My answer for the first number is 2.
Here’s how I got it.
The generic rule for a number in the sequence is: 2^(n – 1) + 1, where n is the position in the sequence.
Note: The teaser doesn’t specify the position of 17. In this case, it’s fifth.
Position 1: (so n = 1) is 2^(1 – 1) + 1 = 2
Position 2: 2^(2 – 1) + 1 = 3
Position 3: 2^(3 – 1) + 1 = 5
Position 4: 2^(4 – 1) + 1 = 9
Position 5: 2^(5 – 1) + 1 = 17
For the curious, the next 5 numbers of the sequence would be: