Maya’s mother asked her to buy some stamps. The available stamps were 3 cents, 9 cents, 11 cents, 17 cents and 21 cents. Her mother asked her to buy eight each of three stamps and nine of each of the remaining two stamps. Unfortunately, Maya forgot which stamps she was supposed to buy eight and nine of. Luckily, her mother had given her $5, the exact amount required to buy the stamps. Which stamps did she buy?
The Pope has it but he does not use it. Your father has it but your mother uses it. Nuns do not need it. Arnold Schwarzenneger has a big one, Michael J. Fox’s is quite small. What is it?
A father gathered his three sons and told them he would die soon and needed to decide which son would inherit his land. He gave them the following test.
“Go to the market and purchase something that is large enough to fill my bedroom, but small enough to fit in your pocket. Based on what you bring I will decide which of you is wisest.”
All three sons went to the market in search of something to satisfy their father’s demands. When they returned the father gathered them in his bedroom.
The first son put down pieces of cloth that he had bought and laid them end to end across the room, but it barely covered any of the floor.
The second son laid down hay but there was only enough to cover part of the floor.
The third son showed his father what he had purchased and the father announced, “You are truly the wisest and will inherit my land.”
A man hiked through the woods with his dog and saw three coyotes, six wolf cubs, seven bunnies, nine squirrels and thirteen chipmunks. How many total feet were there?
Augustus loves candy and much to his delight, his three favorites are on sale. One each of gum, chocolate and caramel cost 40 cents. A caramel is over three times the price of gum. Six gums are worth more than chocolate. A caramel plus two gums cost less than chocolate. What is the price of each candy?
The problem works out to a set of three equations:
b + c + d = 22
a + c + e = 22
a + b + c + d + e = 30
Solving for c = 14, leaving d = 8 – b and e = 8 – a. In other words, c must be 14, but the other two numbers just have to add up to 8. The requirement that they be unique rules out 4 + 4, so you’re left to choose from the following combations for b + d and a + e:
0 + 8
1 + 7
2 + 6
3 + 5