Alfred is at the bank to cash his $200 check. He tells the cashier he would like some one dollar bills, ten times as many two dollar bills and the rest in fives.
How many of each denomination does the cashier need to give Alfred?
We know that in order to give the rest of the amount in fives, the sum of the one and two dollar bills needs to be divisible by five (i.e. end in 0 or 5).
If we start with a single one dollar bill, we’d need ten two dollar bills to satisfy the request, making $21. But we need a sum that is divisible by 5. So we keep going up, like so:
I serve many, confirmed by how healthy those I serve are. Yet after they’re successful they forget about me. It’s true, sometimes I hit them and they’re often bloody, but they don’t mind.
A doctor (more specifically, an obstetrician) or a midwife. They deliver thousands of healthy babies but they are soon forgotten. Sometimes they smack the baby on the butt to clear the airway, and newborn babies can have blood on them from the placenta being pulled from the walls of the uterus or from an episiotomy.
This is a place. The first letter is after A and before Z but nowhere in between. You can bring as many people as you want, as long as they’re all dead. Where is it?
The cemetery. The letter C is after A and before Z, and it’s not found in the word “between”. The cemetery won’t take live ones. Fortunately I don’t speak from experience on that.
There are two tricks to this one. The first is 1 × 0. But it’s mostly there as a distraction. Yes, 1 × 0 is 0, but that doesn’t affect anything else in the equation. The second, far trickier element is that the lines ending with 1 don’t have a + sign next to them. That means they should be combined with the following line.
