Find the names of 10 gems or precious stones hidden in the following story. Each one spans at least two words.
Sir Gade rode toward a castle atop a zebra at a steady gallop, a long way from home. He arrived at the gate and the keeper knelt in shame. “Thy steed must be tired.” Sir Gade replied, “I am on direct orders from the King. Let me through.” A cougar, nettled by the noise, emerged from a shrub. “You must save me!” cried the gate man. Sir Gade, eyes filled with rancor, alighted and gazed toward the sky. An item fell from his cloak as drove his sword into the cougar’s spine. “Let me pass!” cried Sir Gade. The gate keeper, stunned from his saga, tentatively opened the gate, then retrieved the fallen item.
1. topaz – “atop a zebra” 2. opal – “gallop, a long” 3. amethyst – “shame. Thy steed” 4. diamond – “replied, I am on direct” 5. garnet – “cougar, nettled” 6. ruby – “shrub. You” 7. coral – “rancor, alighted” 8. kyanite – “sky. An item” 9. spinel – “spine. Let” 10. agate – “saga, tentatively”
Sir Gade rode toward a castle atop a zebra at a steady gallop, a long way from home. He arrived at the gate and the keeper knelt in shame. “Thy steed must be tired.” Sir Gade replied, “I am on direct orders from the King. Let me through.” A cougar, nettled by the noise, emerged from a shrub. “You must save me!” cried the gate man. Sir Gade, eyes filled with rancor, alighted and gazed toward the sky. An item fell from his cloak as drove his sword into the cougar’s spine. “Let me pass!” cried Sir Gade. The gate keeper, stunned from his saga, tentatively opened the gate, then retrieved the fallen item.
Her birthday is December 31st. Today is January 1st so she was 7 two days ago, and turned 7 last year. Now she’s 8 and will turn 9 this year. And next year she’ll turn 10.
For example, if today is 01 Jan 2015:
30 Dec 2014 = age 7 (two days ago) 01 Jan 2015 = age 8 (today, she turned 8 on 31 Dec 2014, which was last year) 31 Dec 2015 = age 9 (her birthday this year) 31 Dec 2016 = age 10 (her birthday next year)
Fred was almost done packing for the day, with five packages left. Unfortunately, Fred dropped the labels and had no idea which label went to which package. What is the probability that Fred managed to correctly label exactly four of the five packages?
Zero. If Fred had correctly labeled four packages, the fifth label would belong to the fifth package and all packages would be correctly labeled. Therefore it is impossible to mislabel exactly four packages.
You have a lighter and two fuses that take exactly one hour to burn, but they don’t burn at a steady rate. For example, one fuse could take 59 minutes to burn the first inch and then burn the rest of the fuse in the last minute.
How would you use these two fuses to measure 45 minutes?
Light the first fuse on both ends and the second fuse at only one end. When the first fuse burns out you know 30 minutes have passed. Light the other end of the second fuse and when it burns out, 45 minutes have passed.
As a whole, I am both safe and secure. Behead me, I become a place of meeting. Behead me again, I am the partner of ready. Restore me, I become the domain of beasts.
Stable. A table is a place of meeting. Able and ready is a common phrase, and a stable is where beasts reside (beasts of burden, not beasts like the one in Beauty and the Beast who lived in a glorious castle but the west wing was forbidden to enter until Belle…I’ve said too much!).
Everly and I were playing on the merry-go-round at the local park. It was very large and we stood on opposite sides. As we spun the merry-go-round counter-clockwise, I threw a ball to Everly. Did the ball go to Everly, to the right or left of them?