From a basket of mangoes when counted in twos there was one extra,
counted in threes there were two extra,
counted in fours there were three extra,
counted in fives there were four extra,
counted in sixes there were five extra,
but counted in sevens there were no extras.
At least how many mangoes were there in the basket?
119. The number has to be evenly divisible by seven for there to be no extras when counting in sevens, and it has to be odd in order for there to be one extra when counting by twos. It also can’t be evenly divisible by three through six. 119 is the first odd multiple of 7 that satisfies the requirements.
Alternatively:
n is a multiple of 7, and 1 short of a multiple of 3 or 4 or 5 or 6
Division by 6 takes care of division by 3, so n+1 = 4 x 5 x 6 x K
(where K will ensure it’s a multiple of 7)
So n = 119*K, and 119 is divisible by 7, so K = 1 and n = 119
Tom had some mangoes. Then he grouped them in heaps of 4s, 3 remained and when he put them in heaps of 8s, 7 remained. Find the number of mangoes he had.
4 Comments on "How Many Mangoes?"
vats says
August 25, 2014 @ 12:37
119
Ramón says
April 17, 2015 @ 19:17
Alternatively:
n is a multiple of 7, and 1 short of a multiple of 3 or 4 or 5 or 6
Division by 6 takes care of division by 3, so n+1 = 4 x 5 x 6 x K
(where K will ensure it’s a multiple of 7)
So n = 119*K, and 119 is divisible by 7, so K = 1 and n = 119
Ivan says
October 22, 2018 @ 03:41
Tom had some mangoes. Then he grouped them in heaps of 4s, 3 remained and when he put them in heaps of 8s, 7 remained. Find the number of mangoes he had.
shan says
April 10, 2020 @ 05:45
539…..
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